W trójąt równoramienny ABC, AC=BC wpisano okrąg o środku O. Oblicz miary kątów trójkąta jeżeli AOB= 130.
|∢AOB| = 130° |∢OBA| = (180°-130°):2=25° |∢CAB| = 2*25°=50° |∢ACB| = 180° - (2*50°)=80° |∢CAB| = 50° |∢ACB| = 80° |∢ABC| = 50°
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|∢AOB| = 130°
|∢OBA| = (180°-130°):2=25°
|∢CAB| = 2*25°=50°
|∢ACB| = 180° - (2*50°)=80°
|∢CAB| = 50°
|∢ACB| = 80°
|∢ABC| = 50°