December 2018 1 161 Report
Rozwiąż równanie:
4^{tg^2x} =80- 2^\frac{1}{cos^2x} w zbiorze  (\frac{-3 \pi }{2}, \frac{3 \pi }{2}) - { \frac{{- \pi }{2}, \frac{ \pi }{2} }

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