rozwiąż równanie xdo 3+4xdo2-8x-32=0
x³+4x²-8x-32=0
x²(x+4)-8(x+4)=0
(x²-8)(x+4)=0
x²-8=0 lub x+4=0
x²=8 x=-4
x=2√2 lub x=-2√2
x³ + 4x² - 8x - 32 = 0
x²(x + 4) - 8(x + 4) = 0
(x² - 8)(x + 4) =0
x² - 8 = 0 ∨ x + 4 = 0
x² = 8 x = -4
x = 2√2 ∨x = -2√2
odp. x = 2√2 ∨ x = -2√2 ∨ x = -4
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x³+4x²-8x-32=0
x²(x+4)-8(x+4)=0
(x²-8)(x+4)=0
x²-8=0 lub x+4=0
x²=8 x=-4
x=2√2 lub x=-2√2
x³ + 4x² - 8x - 32 = 0
x²(x + 4) - 8(x + 4) = 0
(x² - 8)(x + 4) =0
x² - 8 = 0 ∨ x + 4 = 0
x² = 8 x = -4
x = 2√2 ∨x = -2√2
odp. x = 2√2 ∨ x = -2√2 ∨ x = -4