rozwiąż równanie : (x+3)(x-3)-2(3x-2)=(x-4)(x-4)
(x+3)(x-3)-2(3x-2)=(x-4)(x-4)
x^2 -3x+3x -9 -6x+4 = x^2 -4x - 4x + 16
x^2 -5= x^2 -8x + 16
8x= 21
x=21/8
x²-3x+3x-9-6x+4=x²-4x-4x+16
x²-5= x²-8x+16
8x= 21 | \8
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(x+3)(x-3)-2(3x-2)=(x-4)(x-4)
x^2 -3x+3x -9 -6x+4 = x^2 -4x - 4x + 16
x^2 -5= x^2 -8x + 16
8x= 21
x=21/8
(x+3)(x-3)-2(3x-2)=(x-4)(x-4)
x²-3x+3x-9-6x+4=x²-4x-4x+16
x²-5= x²-8x+16
8x= 21 | \8
x=21/8