Rozwiąż równanie:
x³-12x²+x-12=0
x²(x-12)+(x-12)=0
(x²+1)(x-12)=0
x²+1=0 lub x-12=0
brak x=12
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x³-12x²+x-12=0
x²(x-12)+(x-12)=0
(x²+1)(x-12)=0
x²+1=0 lub x-12=0
brak x=12