log2/3 3/2=c
Bardzo proszę o wyjaśnienie roziązania.
log(a) b = c wtedy i tylko wtedy gdy a^c = b
czyli u nas otrzymujemy
log(2/3) 3/2 = c
(2/3)^c = 3/2
(2/3)^c = (2/3)^(-1)
c = -1
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log(a) b = c wtedy i tylko wtedy gdy a^c = b
czyli u nas otrzymujemy
log(2/3) 3/2 = c
(2/3)^c = 3/2
(2/3)^c = (2/3)^(-1)
c = -1