October 2018 1 88 Report

Rozwiąż równanie lub nierówność.
a) (x-3)² - (x²+2)² ≤ -(x²-4)(x²+4)+8-3x²
b) (2x+7)³+3(x-2)(x+2)=8x³+(x+7)²
c) |x|=6
d) |x-2|=8
e) |x+3|<7
f) |x-2|≥8
g) |2x-14|=2
h) |x+6|>10
i) |2-x|≤10
j) |x+14|≥16


More Questions From This User See All

Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.