Question

Rozwiąż równanie kwadratowe


a) (x-3)^2 = (2x-1)(x-3)
b) x^2+4x+4 - (x+2)(3x-4)

Z góry dziękuję!

Answer 1

A) (x - 3)² = (2x - 1)(x - 3)(x - 3)² - (2x - 1)(x - 3) = 0(x- 3)[(x - 3) - (2x - 1)] = 0(x - 3)(x - 3 - 2x + 1) = 0(x - 3)(- x - 2) = 0x - 3 = 0 v - x - 2 = 0x - 3 = 0x = 3  



b) x² + 4x + 4 = (x + 2)(3x - 4)(x + 2)² = (x + 2)(3x - 4)(x + 2)² - (x + 2)(3x - 4) = 0(x + 2)[(x + 2) - (3x - 4)] = 0(x + 2)((x + 2 - 3x + 4) = 0(x + 2)(- 2x + 6) = 0x + 2 = 0 v - 2x + 6 = 0x + 2 = 0x = - 2