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dziedzina: x ≠ 0
(1/2)^{(1- x)/x} ≤ 1
(1/2)^{(1- x)/x} ≤ (1/2)^{0}
1/2 < 1
(1- x)/x ≥ 0 i x ≠ 0
x(x - 1) ≤ 0 i x ≠ 0
x ∈ (0, 1>
b) 16^{x/(x + 3)} = 4 * (2^{x}/8)^{1/(2x + 5)}
dziedzina: x ≠ - 3 i x ≠ - 5/2
2^{4x/(x + 3)} = 2^{2} * (2^{x}/2^{3})^{1/(2x + 5)}
2^{4x/(x + 3)} = 2^{2} * (2^{x - 3})^{1/(2x + 5)}
2^{4x/(x + 3)} = 2^{2} * 2^{(x - 3)/(2x + 5)}
2^{4x/(x + 3)} = 2^{2 + (x - 3)/(2x + 5)}
4x/(x + 3) = 2 + (x - 3)/(2x + 5)
4x(2x + 5) = (2x + 6)(2x + 5) + x² - 9
8x² + 20x = 4x² + 22x + 30 + x² - 9
3x² - 2x - 21 = 0
Δ = 4 + 4*63 = 4*64 = 16*16
x = (2 ± 16)/6
x = 3 ∨ x = - 2 1/3
jak masz pytania to pisz na pw