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[3x(x-3)(x+2)]/(x-3) + [(2x-1)(x-3)(x+2)]/(x+2)= [4(x-3)(x+2)]/[(x-3)(x+2)] tteraz skracamy wyrazy podobne
3x(x+2) + (2x-1)(x-3)= 4
3x²+6x+2x²-6x-x+3=4
5x²-x-1=0
Δ=(-1)²-4*5*1=1-20=-19
Δ<0
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