Zał.
Zatem:
Odp.
(3x+2) / (2x-4) = (3x+1) / (3x-2)
(3x+2)*(3x-2) = (2x-4)*(3x+1)
9x²-6x+6x-4 = 6x²+2x-12x-4
9x²-6x+6x-4-6x²-2x+12x+4=0
3x²+10x=0
Δ=100
√Δ=10
x₁=-10-10 / 6 = -20/6
x₂=-10+10 / 6 = 0
II sposób:
x(3x+10)=0
x=0 lub 3x+10=0
3x=-10
x=-10/3
x=-3⅓
x=0 lub x=-3⅓
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Zał.
Zatem:
Odp.
(3x+2) / (2x-4) = (3x+1) / (3x-2)
(3x+2)*(3x-2) = (2x-4)*(3x+1)
9x²-6x+6x-4 = 6x²+2x-12x-4
9x²-6x+6x-4-6x²-2x+12x+4=0
3x²+10x=0
Δ=100
√Δ=10
x₁=-10-10 / 6 = -20/6
x₂=-10+10 / 6 = 0
II sposób:
x(3x+10)=0
x=0 lub 3x+10=0
3x=-10
x=-10/3
x=-3⅓
x=0 lub x=-3⅓