Rozwiąż równanie 2xdo3potęgi +8xdo potęgi -3x-12=0
2x³+8x²-3x-12=0
2x²(x+4)-3(x+4)=0
(x+3)(2x²-3)=0
(x+3)(√2x-√3)(√2x+√3)=0
x=-3 v x=√3/√2=½√6 v x=-√3/√2=-½√6
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2x³+8x²-3x-12=0
2x²(x+4)-3(x+4)=0
(x+3)(2x²-3)=0
(x+3)(√2x-√3)(√2x+√3)=0
x=-3 v x=√3/√2=½√6 v x=-√3/√2=-½√6