Rozwiąż równanie: 10x^2=-2x+2..... to ma byc z deltą..
10x²=-2x+2
10x²+2x-2=0
a=10,b=2,c=-2
Δ=b²-4ac=2²-4*10*(-2)=4+80=84
√Δ=√84=√4*21=2√21
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
10x²=-2x+2
10x²+2x-2=0
a=10,b=2,c=-2
Δ=b²-4ac=2²-4*10*(-2)=4+80=84
√Δ=√84=√4*21=2√21