October 2018 1 15 Report

rozwiąż równania

a) \frac{x}{3}-\frac{x}{2}=\frac{5}{6}

b) \frac{x+1}{2}-\frac{x-1}{4}=1\frac{1}{2}

c) 1\frac{2}{3}-\frac{1}{2}x=\frac{x}{6}-1

d) 2x-\frac{3-4x}{5}=3+x

e) \frac{1-x}{3}+\frac{2x+3}{5}=2-\frac{2(x+1)}{15}

f) \frac{1}{2}(3x-1)-\frac{4x+3}{10}-1=\frac{3}{10}-\frac{1-x}{5}+x

g) (x+2)^{2} - (x-4)^{2}=-18

h) (3x-1)^{2}-(2x+3)^{2}=4(x+1)^{2}+x(x-12)-9

i) (5-2x)(5+2x)+(2x+1)^{2}=(x-2)^{2}-x(x+2)

j) 2x(x+7)-(3x+2)^{2}=-2-7(x-2)^{2}

k) (\sqrt{2}x-1)(\sqrt{2}x+1)+3x-2=(3-x)^{2}+x(x-1)

trzeba pamietac o wzorach skróconego mnozenia


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