Odpowiedź:
a)
(4-x)(x+5)(2x-3)=0
4-x=0
x+5=0
2x-3=0
x=4
x=-5
x=3/2
x1=-5
x2=3/2
x3=4
b) (2x²-x-1)(x+3)=0
2x²-x-1=0
x+3=0
x=-1/2
x=1
x=-3
x1=-3
x2=-1/2
x3=1
c) x³+4x²-2x-8=0
x²*(x+4)-2(x²-2)=0
(x+4)*(x²-2)=0
x+4=0
x²-2=0
x=-4
x=-√2
x=√2
x1=-4
x2=-√2
x3=√2
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Odpowiedź:
a)
(4-x)(x+5)(2x-3)=0
4-x=0
x+5=0
2x-3=0
x=4
x=-5
x=3/2
x1=-5
x2=3/2
x3=4
b) (2x²-x-1)(x+3)=0
2x²-x-1=0
x+3=0
x=-1/2
x=1
x=-3
x1=-3
x2=-1/2
x3=1
c) x³+4x²-2x-8=0
x²*(x+4)-2(x²-2)=0
(x+4)*(x²-2)=0
x+4=0
x²-2=0
x=-4
x=-√2
x=√2
x1=-4
x2=-√2
x3=√2
Szczegółowe wyjaśnienie: