Rozwiąż równania
2t-(3t+1)=6
-(4+x)=2(3-x)
3(y+6)-y=2(y+9)
(x-7)-2(3x+5)=3
PROSZĘ O PEŁNE OBLICZENIA!!!
2t-3t-1=6
2t-3t=6+1
-1t=7 /:-1
t=-7
-4-x=6-2x
-x+2x=6+4
x=10
3y+18-y=2y+18
3y-y-2y=18-18
0=0
x-7-6x-10=3
x-6x=3+10+7
-5x=20 /:-5
x=-4
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2t-(3t+1)=6
2t-3t-1=6
2t-3t=6+1
-1t=7 /:-1
t=-7
-(4+x)=2(3-x)
-4-x=6-2x
-x+2x=6+4
x=10
3(y+6)-y=2(y+9)
3y+18-y=2y+18
3y-y-2y=18-18
0=0
(x-7)-2(3x+5)=3
x-7-6x-10=3
x-6x=3+10+7
-5x=20 /:-5
x=-4
LICZĘ NA NAJ :)