October 2018 1 32 Report

Rozwiąż równania trygonometryczne:

1)\ 2sin^{2}x+sinxcosx+3cos^{2}x=3\\ 2)2cos2x+2cos4x+3sin^{2}2x=1\\ 3)(cosx+sinx)^{2}-sin2x=\frac{1}{2}sin^{2}2x+2cos^{4}\\

PROSZĘ O KLAROWNE WYTŁUMACZENIE


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