rozwiąż równania funkcji kwadratowej y=ax²+bx+c
a. 3(x+2)² - 2(x-2)(x+3) = 8
b.(4x+1)² - (2x+1)²=(3x+1)²
c. (3x-2)² + 2x(7 - 3x) - 4x² = 5 -(2x-5)²
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a) 3(x+2)² -2(x-2)(x+3)=8
3(x²+4x+4)-2(x²+3x-2x-5)=8
3x²+12x+12-2x²-2x+12=8
x²+10x+24=8
x²+10x+16=0
Δ=b²-4ac
Δ=100-4·1·16
Δ=36
√Δ=6
b)(4x+1)²-(2x+1)²=(3x+1)²
16x²+8x+1-(4x²+4x+1)=9x²+6x+1
16x²+8x+1-4x²-4x-1-9x²-6x-1=0
3x²-2x-1=0
Δ=4-4·3·(-1)
Δ=16
√Δ=4
c)(3x-2)²+2x(7-3x)-4x²=5-(2x-5)²
9x²-12x+4+14x-6x²-4x²=5-(4x²-20x+25)
-x²+2x+4=5-4x²+20x-25
-x²+2x+4-5+4x²-20+25=0
3x²-18x+24=0
Δ=324-4·3·24
Δ=36
√Δ=6