Question

rozwiąż równania: ^ - do potęgi
a) x^3 + 2x^2 + x = 0

b) 2x^3 - 12x^2 + 18x = 0

c) (x+3)^2 = 4

Answer 1

a)

x(x²-2x+1)=0

x(x-1)²=0

x=0 ∨ x=1

b)

2x(x²-6x+9)=0

2x(x-3)²=0

x=0 ∨ x=3

c)

(x+3)²=4

x+3 = 2 ∨ x+3 = -2

x = -1   ∨ x = -5

Answer 2

a)

x ( x^2 + 2x + 1 ) = 0

a=1 b=2 c=1

delta = b^2 - 4ac = 4-4=0

x0= - b/2a = -2/2 = -1

x=0

x=-1

 

b)

2x ( x^2-6x+9 ) =0

2x=0

x=0

 

delta = 36-36=0

x= 6/2=3

x=3

x=0

 

c)

x^2+6x+9-4=0

x^2+6x+5=0

 

delta = 36-20=16 pierwiastek z delty=4

x1=-6-4/2=-5

x2=-6+4/2= -1