Rozwiąż podane układy równań metodą podstawiania
Pierwszy układ;
x - 2y =3
-2x + y = 0
drugi kład;
2x + y = 9
5x - 4y = 3
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x - 2y =3
-2x + y = 0
x=3+2y
-2(3+2y)+y=0
-6-4y+y=0
-3y=6/:(-3)
y=-2
x=3+2y
x=3+2*(-2)
x=3-4
x=-1
2x + y = 9
5x - 4y = 3
y=9-2x
5x-4(9-2x)=3
5x-36+8x=3
13x=39/:13
x=3
y=9-2x
y=9-2*3
y=9-6
y=3
licze na naj ;d
{x - 2y =3
{-2x + y = 0
{x=2y+3
{-2(2y+3)+y=0
[x=2y+3
{-4y-6+y=0
{x=2y+3
{-3y=6
{x=2·(-2)+3=-4+3=-1
{y=-2
{x=-1
{2x + y = 9
{5x - 4y = 3
{y=9-2x
{5x-4(9-2x)=3
{y=9-2x
{5x-36+8x=3
[y=9-2x
{13x=39
[y=9-2·3=9-6=3
[x=3
{y=3