Rozwiąż nierówności kwadratowe :
1. -x^-5x+6>0
2. x^+x-6<0
3. x^-5x+6<0
4. x^-x-6>(x-2)(x+3)
5. 2(x-2)^>(x-2)(x+3)
6. -(x-1)^>5(x-1)
7. 3x^+4x-4>0
8. (x-4)^+(x-4)(x+2)>0
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1)
-x²-5x+6>0
Δ=25-4*(-1)*6=25+24=49
√Δ=7
x₁=1 x₂=-6
x∈ (-6,1)
2)
x²+x-6 <0
Δ=1-4*(-6)*1=25
√Δ=5
x₁=-3 x₂=2
x∈(-3,2)
3)
x²-5x+6<0
Δ=25-4*6*1=1
√Δ=1
x₁=2 x₂=3
x∈(2,3)
4)
x²-x-6>(x-2)(x+3)
x²-x-6>x²-2x+3x-6
x²-x-6>x²+x-6
-x>x
-2x>0
x<0
5)
2(x-2)²>(x-2)(x+3)
2(x²-4x+4)>x²+x-6
2x²-8x+8-x²-x+6>0
x²-9x+14>0
Δ=81-4*1*14
Δ=25
√Δ=5
x₁=2 x₂=7
x∈(-∞,2) suma (7,+∞)
6)
-(x-1)²>5(x-1)
-x²+2x-1>5x-5
-x²-3x+4>0
Δ=9-4*(-1)*4=9+16=25
√Δ=5
x₁=1 x₂=-4
x∈(-4,1)
7)
3x²+4x-4>0
Δ=16-4*(-4)*3=64
√Δ=8
x₁= -2 x₂= 2/3
x∈(-∞,-2) suma (2/3,+∞)
8)
(x-4)²+(x-4)(x+2)>0
x²-8x+16+x²-4x+2x-8>0
2x²-10x+8>0
Δ=100-4*2*8=36
√Δ=6
x₁=1 x₂=4
x∈(-∞,1) suma (4,+∞)