September 2018 2 10 Report

Rozwiąż nierównośc:

\frac{2}{3}(6x-3) \geq 0</p> <p> </p> <p>\frac{4x-3}{3} - \frac{x+1}{2}\geq\frac{1}{6}

-x - \frac{x-3}{3}-3>0


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