Rozwiąż nierówność:
a) (2x-2)(x-3)<(x-3)(x-4)
(2x-2)(x-3)<(x-3)(x-4)
2x²-6x-2x+6<x²-4x-3x+12
x²-x-6<0
Δ=(-1)²-4*1*(-6)Δ=1+24
Δ=25
√Δ=5
x₁=(-(-1)-5)/(2*1)
x₁=-4/2
x₁=-2
x₂=(-(-1)+5)/(2*1)
x₂=6/2
x₂=3
x∈(-2,3)
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(2x-2)(x-3)<(x-3)(x-4)
2x²-6x-2x+6<x²-4x-3x+12
x²-x-6<0
Δ=(-1)²-4*1*(-6)
Δ=1+24
Δ=25
√Δ=5
x₁=(-(-1)-5)/(2*1)
x₁=-4/2
x₁=-2
x₂=(-(-1)+5)/(2*1)
x₂=6/2
x₂=3
x∈(-2,3)