September 2018 1 33 Report

Rozwiąż nierówność .

8-4(3+x)\geq-12 + 4x \\ 2-\frac{x-5}{2}>4x-9 \ \ / * 2 \\ \frac{3(7-x)}{2}-2\leq-3x \\ \frac{2+x}{3}-\frac{3-x}{6}>-1 \ /*6 \\ \frac{5}{x} - \frac{2(x+1)}{15}>\frac{1}{5} (1+x) \ /*15


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