Rozwiąż nierówność x²+8x+15>0
x²+8x+15>0
Δ=64-4*1*15=64-60=4
√Δ=2
x1=(-8-2)/2=-10/2=-5
x2=(-8+2)/2=-6/2=-3
x∈(-∞;-5)u(-3;+∞)
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x²+8x+15>0
Δ=64-4*1*15=64-60=4
√Δ=2
x1=(-8-2)/2=-10/2=-5
x2=(-8+2)/2=-6/2=-3
x∈(-∞;-5)u(-3;+∞)
licze na naj