rozwiąż nierówność: x^2-3x+1<0
x² - 3x + 1 < 0
Δ = (-3)² - 4 * 1 * 1 = 9 - 4 = 5
√Δ = √5
x1 = (3 - √5)/2
x2 = (3 + √5)/2
+++++ +++++ ramiona paraboli idą w góre
---------o-------------o------------->
x1 --------- x2
odp. x ∈ (x1, x2)
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x² - 3x + 1 < 0
Δ = (-3)² - 4 * 1 * 1 = 9 - 4 = 5
√Δ = √5
x1 = (3 - √5)/2
x2 = (3 + √5)/2
+++++ +++++ ramiona paraboli idą w góre
---------o-------------o------------->
x1 --------- x2
odp. x ∈ (x1, x2)