Rozwiąż nierówność 2(x+1) < -x(x+1).
2(x+1) < -x(x+1)
2x+2<-x²-x
0<-x²-3x-2
Δ = 1
x1 = -1
x2 = -2
0<-(x+1)(x+2)
x ∈ (-2;-1)
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2(x+1) < -x(x+1)
2x+2<-x²-x
0<-x²-3x-2
Δ = 1
x1 = -1
x2 = -2
0<-(x+1)(x+2)
x ∈ (-2;-1)