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x1=(3-1)/-2 = -1
x2=(3+1)/-2= -2
x∈(-∞,-2) u (-1, +∞)
b) (x+5)(x-1)<0
x+5=0 v x-1= 0
x=-5 v x=1
x∈(-5, 1)
c) Δ=64-60=4
x1= (8-2)/2=3
x2= (8+2)/2=5
x∈ {3, 5}
d) -x²=-25/*(-1)
x²=25
|x|=25
x=5 v x=-5
x∈{-5, 5}
e) x(3x+5)=0
x=0 v 3x+5=0
x=0 v 3x=-5
x=0 v x=-5/3
x∈{-5/3, 0}