Rozłóż dany wielomian na czynniki: W(x)=(2x2-5x-3)(2x2-7x+3) x2 to potęga
W(x)=(2x^2-5x-3)(2x^2-7x+3)
2x^2-5x-3
delta=25+24=49
x1=5-7/4=-2/4=-1/2
x2=5+7/4=12/4=3
2x^2-7x+3
delta=49-24=25
x1=7-5/4=2/4=1/2
x2=7+5/4=12/4=3
W(x)=4(x+1/2)(x-3)(x-1/2)(x-3)=(x+1/2)(x-1/2)(x-3)^2
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W(x)=(2x^2-5x-3)(2x^2-7x+3)
2x^2-5x-3
delta=25+24=49
x1=5-7/4=-2/4=-1/2
x2=5+7/4=12/4=3
2x^2-7x+3
delta=49-24=25
x1=7-5/4=2/4=1/2
x2=7+5/4=12/4=3
W(x)=4(x+1/2)(x-3)(x-1/2)(x-3)=(x+1/2)(x-1/2)(x-3)^2