Równanie (x + 2)2 = 9 ile ma rozwiązań ??? i dlaczego???
(x+2)² = 9
x² + 4x + 4 = 9
x² + 4x - 5 = 0
Δ = b²-4ac
Δ = 4² - 4 x 1 x (-5) = 16 - (-20) = 36
√Δ = √36 = 6
x₁ = -b-√Δ/2a
x₁ = -4-6/2 x 1 = -5
x₂ = -b+√Δ/2a
x₂ = -4+6/2 x 1 = 1
Równnie ma dwa rozwiązania: -5 i 1
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(x+2)² = 9
x² + 4x + 4 = 9
x² + 4x - 5 = 0
Δ = b²-4ac
Δ = 4² - 4 x 1 x (-5) = 16 - (-20) = 36
√Δ = √36 = 6
x₁ = -b-√Δ/2a
x₁ = -4-6/2 x 1 = -5
x₂ = -b+√Δ/2a
x₂ = -4+6/2 x 1 = 1
Równnie ma dwa rozwiązania: -5 i 1
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)