6y² = 12x y² = 12x / 6 y² = 2x aplicar (y - k)² = ± 4p(x - h) 4p = 2 p = 2/4 p = ½ (distancia entre el foco y el vértice) F(p, 0) = F(½, 0)
x = -p x = -½
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6y² = 12x
y² = 12x / 6
y² = 2x
aplicar
(y - k)² = ± 4p(x - h)
4p = 2
p = 2/4
p = ½ (distancia entre el foco y el vértice)
F(p, 0) = F(½, 0)
x = -p
x = -½
sustituir numero para graficar y listo