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(2a + 1 + 2b + c)/3 = 17
a +b + c = 36
2a + 2b + c + 1 = 51
a + b + c = 36
2a + 2b + c = 51 - 1 = 50
a + b = 36 - c
2(a +b) + c = 50
2(36 - c) + c = 50
72 - 2c + c = 50
- c = 50 - 72
- c = - 22
c = 22
a + b = 36 - 22 = 14
(a + b)/2 = 14/2 = 7 - średnia arytmetyczna a i b
a+b+c = 36
(2a+1+2b+c) / 3 = 17 /*3
2a + 1+ 2b + c = 51
2a + 2b + c + 1 =51
a + b + a + b + c +1 = 51
a+ b + 36 + 1 = 51
a + b = 51 - 1 - 36
a + b = 14
i średnia arytmetyczna liczb a i b
S = a+b / 2
S = 14/2
S = 7
Odp. Średnia arytmetyczna liczb a i b wynosi 7