r=50m
12 okrążeń w czasie 4 minut
jaka jest szybkość średnia?
Obw. koła = 2πr = 100π m
Vśr. = s/t
s= 12*100π m = 1200π m ≈ (1200*3,14) m = 3768 m
t= 4 min. = 250 s.
Vśr = 3768/250 = 15,072 ≈ 15 m/s
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Obw. koła = 2πr = 100π m
Vśr. = s/t
s= 12*100π m = 1200π m ≈ (1200*3,14) m = 3768 m
t= 4 min. = 250 s.
Vśr = 3768/250 = 15,072 ≈ 15 m/s