Jawaban:
π/6
Penjelasan dengan langkah-langkah:
Misal
81^(sin² x) = a
81^(cos² x) = b
a + b = 30
1 + 29 = 30
2 + 28 = 30
3 + 27 = 30 → coba yang ini
81^(sin² x) = 3
3^(4 . sin² x) = 3^1
4 . sin² x = 1
sin² x = 1/4
sin x = √(1/4)
sin x = 1/2
sudut x = 30°
81^(cos² x) = 27
(3^4)^(cos² 30°) = 3^3
4 . cos² 30° = 3
4 . (cos 30°)² = 3
4 . (1/2 √3)² = 3
4 . 3/4 = 3
3 = 3 (valid)
Maka, x = 30° atau x = π/6
Jawabannya A
Kode Kategorisasi : 10.2.6
Kelas 10
Pelajaran Matematika
Bab 6 - Trigonometri Dasar
Kata kunci : sin x, cos x
A. π/6
81 sin²x = 3
3⁴ (sin x )² = 3
3 ( sin x ) = 3^½
sin x = ½
x = 30°
x = 30/180 π
x = 1/6 π
x = π/6
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Jawaban:
π/6
Penjelasan dengan langkah-langkah:
Misal
81^(sin² x) = a
81^(cos² x) = b
a + b = 30
1 + 29 = 30
2 + 28 = 30
3 + 27 = 30 → coba yang ini
81^(sin² x) = 3
3^(4 . sin² x) = 3^1
4 . sin² x = 1
sin² x = 1/4
sin x = √(1/4)
sin x = 1/2
sudut x = 30°
81^(cos² x) = 27
(3^4)^(cos² 30°) = 3^3
4 . cos² 30° = 3
4 . (cos 30°)² = 3
4 . (1/2 √3)² = 3
4 . 3/4 = 3
3 = 3 (valid)
Maka, x = 30° atau x = π/6
Jawabannya A
Kode Kategorisasi : 10.2.6
Kelas 10
Pelajaran Matematika
Bab 6 - Trigonometri Dasar
Kata kunci : sin x, cos x
Jawaban:
A. π/6
Penjelasan dengan langkah-langkah:
81 sin²x = 3
3⁴ (sin x )² = 3
3 ( sin x ) = 3^½
sin x = ½
x = 30°
x = 30/180 π
x = 1/6 π
x = π/6