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m = 34 g de NH3
P = 1 atm.
T = 0º + 273 = 273 K
R = 0.082 L · atm/mol· K
P · V = n · R · T
CALCULAR MOLES=
n = masa/ Mm
n = 34 g / 17 g/mol = 2 mol
Calcular V = ?
V = n · R · T
P
V = 2 moles x 0.082 L · atm/mol· K x 273 K = 44,0772 L
1 atm.