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dane m=5kg, t.t = 328*C, to=0*C, l=30 000J/kg, c=100 J/kgK
szukane Q
Q = Q krz + Q ochł = m*l + m*c*[t.t - to] = 5kg*30kJ/kg + 5kg*100J/kgK*328K =
Q = 150kJ + 164kJ = 314 kJ ciepła zostanie oddanych w tym procesie.
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