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Z def jednokladnosci:
SA'=k*SA (dzialamy na wektorach)
a)
SA'=[-3,4]
SA=[a+1,b-1]
2SA=[2a+2,2b-2]
2a+2=-3
2b-2=4
a=-5/2
b=3
b)SA'=[5,7]
SA=[2a-1,b+2]
2SA=[4a-2,2b+4]
4a-2=5
2b+4=7
a=7/4
b=3/2
Ad. Jesli mam jakis zly wynik, to napisz gdzie, postaram sie poprawic;)