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mFe₂O₃=2*56u+3*16u=160u
5Fe + 7H₂O---->Fe₂O₃ + Fe₃O₄ + 7H₂
a)
5*56g Fe-----7*22,4dm³ wodoru
10g Fe----------xdm³ wodoru
x=5,6dm³ wodoru
b)
5*56g Fe-------160g Fe₂O₃
10g Fe-----------xg Fe₂O₃
x=5,7g Fe₂O₃
14g Fe₂O₃ + Fe₃O₄------100%
5,7g Fe₂O₃-----------------x%
x=40,7% Fe₂O₃