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a=bok podstawy
2a= krawędź boczna
d podstawy=a√2
z pitagorasa:
9²=(a√2)²+(2a)²
81=2a²+4a²
81=6a²
a²=81:6
a=9:√6
2a=2×9/√6=¹⁸/√₆
pole boczne:4×⁹/√₆×¹⁸/√₆=108cm²