Question

Przekształć iloczyny na sumy;
a](√3+1)(2√3-2)
b](x+√2)(2√2+x)
√-pierwiastek

Answer 1

A](√3+1)(2√3-2)=2*(√3)²-2√3+2√3-2
b](x+√2)(2√2+x)=2√2x+x²+2*2+√2x=3√2x+x²+4

Answer 2

A)
(√3+1) * (2√3-2) = √3 * (2√3-2) + 1 * (2√3-2) =
√3 * 2√3 - √3 * 2 + 2√3 - 2 = 6 - 2 * √3 + 2√3 - 2 = 6 +(- 2)

b) (x+√2)(2√2+x) = x * 2√2 + x * x + √2 * 2√2 + √2 * x =
x² + 3x√2 + 4