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a - bok przekroju osiowego
l = a√2 = 4√2
a = 4
d - średnica podstawy = a = 4
h - wysokość walca = a = 4
Pp - pole podstawy = πd²/4 = π4²/4 = 16π/4 = 4π
Pb - pole powierzchni bocznej = πdh = 4π * 4= 16π
Pc - pole powierzchni całkowitej = 2 * Pp + Pb = 2 * 4π + 16π = 8π + 16π
= 24π
V - objętość walca = Pp * h = 4π * 4 = 16π