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a=l
l=6 cm
r=1/2a
r=3 cm
P=πr(r+l)
P=π3(3+6)
P=3π*9
P=27π cm²
l=6
h=6
P pow.bocznej stożka = πrl
P=3,14 × 3 × 6
P=56,52
P podstawy stożka = πr²
P=3,14 × 3²
P=3,14 × 9
P= 28,26
P pow.całkowitej= Pp + Pb
Pc= 56,52 + 28,26
Pc= 84,78 cm²