Question

Przekatne rombu maja dlugosc 6 i 8 . oblicz pole dlugosc boku i wysokosc rombu

Answer 1

d1 = 6

d2 = 8

 

P = 1/2 * d1 * d2 = 1/2 * 6 * 8 = 24cm^2  -----  pole rombu

 

 

(1/2d1)^2 + (1/2d2)^2 = a^2

3^2 + 4^2 = a^2

a^2 = 9 + 16

a^2 = 25

a = 5   -------  bok rombu

 

P = a * h

24 = 5 * h

h = 24 : 5

h = 24/5 = 48/10

h = 4,8  --------------  wysokość rombu