przedstaw wyrazenia w postaci najprostrzej sumy algebraicznej
a)(-2xy)²-(1-x²)(y²-1)+2xy
b)(a+b)(b+a)
c)(2c√₂-3)²
a) (-2xy)²-(1-x²)(y²-1)+2xy=
=4x²y²-(y²-1-x²y²+x²)+2xy=
=4x²y²-y²+1+x²y²-x²+2xy=
=5x²y²+2xy-x²-y²+1
b) (a+b)(b+a)=
=(a+b)(a+b)= <- dodawanie jest przemienne
=(a+b)²=
=a²+2ab+b²
c) (2c√2-3)²=
= 8c²-12√2c+9
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a) (-2xy)²-(1-x²)(y²-1)+2xy=
=4x²y²-(y²-1-x²y²+x²)+2xy=
=4x²y²-y²+1+x²y²-x²+2xy=
=5x²y²+2xy-x²-y²+1
b) (a+b)(b+a)=
=(a+b)(a+b)= <- dodawanie jest przemienne
=(a+b)²=
=a²+2ab+b²
c) (2c√2-3)²=
= 8c²-12√2c+9