Przedstaw w postaci iloczynu : (a-1)(b+c)-(1-a)(b-c)
(a-1)(b+c)+(a-1)(b-c)=(a-1)(b+c+b-c)=2b(a-1)
(a-1)* (b+c)-(1-a)*(b-c)=a-1*b+c-1-a*b-c=2b
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(a-1)(b+c)+(a-1)(b-c)=(a-1)(b+c+b-c)=2b(a-1)
(a-1)* (b+c)-(1-a)*(b-c)=a-1*b+c-1-a*b-c=2b