przedstaw powyższe równanie w postatci kierunkowej :
2x-y+2=0
10x+5y-5=0
-trzy drugie x +½y-2=0
½x-¾y- 2¼=o
2x-y+2=0 ----> -y=-2x-2 /-1 = y=2x+2
10x+5y-5=0 ---> 5y=-10x+5/5 = y=-2x+1
3/2x+1/2y-2=0 ---> 1/2y=-3/2x+2 x2 = y=6/4+4
1/2x-3/4y-2 1/4 =0 ----> -3/4y=-1/2x+ 2 1/4 /-3/4 = y= 4/6x+3
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2x-y+2=0 ----> -y=-2x-2 /-1 = y=2x+2
10x+5y-5=0 ---> 5y=-10x+5/5 = y=-2x+1
3/2x+1/2y-2=0 ---> 1/2y=-3/2x+2 x2 = y=6/4+4
1/2x-3/4y-2 1/4 =0 ----> -3/4y=-1/2x+ 2 1/4 /-3/4 = y= 4/6x+3