Question

Przedstaw potęgi w postaci potęg o wyklaniku 18:

8^6

512^2

400^9

(-27)^6

(-1)^10

Answer 1

8^6=2^(3*6)=2^18

512^2=2^(9*2)=2^18

400^9=20^(2*9)=20^18

(-27)^6=(-3)^(3*6)=(-3)^18

(-1)^10=1=(-1)^18

Answer 2

8^6 =2^ (3·6) = 2^18

512^2 = 2^ (9·2 ) = 2^18

400^9=20^ (2·9)  = 20^18

(-27)^6=(-3)^ (3·6)  = (-3)^18

(-1)^10=1 =  (-1) ^18