Question

prosze o rozwiązanie zadania 10 i działań po wyżej .

Answer 1

a) √2* √6 = √12 = √4*3 = 2√3

b) 2√3* √18 = 2√3*18 = 2√54 = 2√6*9= 6√6

c) 7√10 * ½√5 = 3½√50 = 3,5*√25*2 = 17,5√2

d) √50+ √2 = √25*2 + √2 = 5√2+ √2 = 6√2

e) √300- 2√3 = √100*3 - 2√3 = 10√3- 2√3 = 8√3

f) -2√32 - 2√8 = -2√2*16 - 2√4*2 = -8√2 -4√2 = -12√2

 

zadanie10:

 

a) √2* √4½ = √2*9/2 = √9 = 3

b) √2⅔: √⅔ = √8/3* 3/2 = √4 = 2

c) √6,4 : √10 = √6,4:10 = √0,64 = 0,8

d) ∛10 * ∛0,1 = ∛1 = 1

e) ∛2⅔ * ∛1/9 = ∛8/27 = ⅔

f) ∛2,7/∛100 = ∛0,027 = 0,3

g) ∛-9 * ∛3 = ∛-9*3 = ∛-27 = -3

h) ∛128/∛-2 = ∛-64 = -4

i) ∛-0,5*∛4/∛16= ∛-2/16 = ∛-⅛ = -½

 

Ps. Znak / oznacza ułamek,

W razie pytań pisz :)