Question

Prosze o rozwiazanie tego:

16x²-8x+1>0

Answer 1

16x²-8x+1>0
8x(2x-1)+1>0
8x(2x-1)>-1
8x>-1 |:8 ∨ 2x-1>-1
x>-⅛ ∨ 2x>-1+1
2x>0 |:2
x>-⅛ ∨ x>0

x∈R

Answer 2

Δ=b²-4ac=(-8)²-4*16*1=64-64=0
a₀=-b/2a=8/2*16=8/32=¼
x∈R{¼}