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Zajmuje sie pierwsza linijka
a-krawedz podstawy
b-krawedz boczna
a=2
b=3
Pp=![\frac{a^2\sqrt{3}}{4}=\frac{2^2\sqrt{3}}{4}=\frac{4\sqrt{3}}{4}=\sqrt{3} \frac{a^2\sqrt{3}}{4}=\frac{2^2\sqrt{3}}{4}=\frac{4\sqrt{3}}{4}=\sqrt{3}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%5E2%5Csqrt%7B3%7D%7D%7B4%7D%3D%5Cfrac%7B2%5E2%5Csqrt%7B3%7D%7D%7B4%7D%3D%5Cfrac%7B4%5Csqrt%7B3%7D%7D%7B4%7D%3D%5Csqrt%7B3%7D)
Pb=3*2*3=3*6=18
Pc= 2Pp+Pb=2√3+18
Druga linijka
a-krawedz podstawy
b-krawedz boczna
b=3
Pb=27
Pb=3*a*b
27=3**a*3
27=9a |:9
a=3
Pp=![\frac{a^2\sqrt{3}}{4}=\frac{3^2\sqrt{3}}{4}=\frac{9\sqrt{3}}{4}=\frac{9}{4}\sqrt{3} \frac{a^2\sqrt{3}}{4}=\frac{3^2\sqrt{3}}{4}=\frac{9\sqrt{3}}{4}=\frac{9}{4}\sqrt{3}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%5E2%5Csqrt%7B3%7D%7D%7B4%7D%3D%5Cfrac%7B3%5E2%5Csqrt%7B3%7D%7D%7B4%7D%3D%5Cfrac%7B9%5Csqrt%7B3%7D%7D%7B4%7D%3D%5Cfrac%7B9%7D%7B4%7D%5Csqrt%7B3%7D)
Pc=Pp+pb=2*![\frac{9}{4}\sqrt{3} +27=\frac{9}{2}\sqrt{3} +27 \frac{9}{4}\sqrt{3} +27=\frac{9}{2}\sqrt{3} +27](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B4%7D%5Csqrt%7B3%7D+%2B27%3D%5Cfrac%7B9%7D%7B2%7D%5Csqrt%7B3%7D+%2B27)